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Admin ob 07:08, 27. oktober 2010
2010-10-27T07:08:08Z
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>1. Porabnik z zaporedno vezavo upora in tuljave obremenjuje električno omrežje 230 V/50 Hz z močjo 100 VA in povzroča fazni kot ''φ'' = 38 º. Izračunaj delovno moč, ohmsko upornost in induktivnost porabnika.|||</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>1. Porabnik z zaporedno vezavo upora in tuljave obremenjuje električno omrežje 230 V/50 Hz z močjo 100 VA in povzroča fazni kot ''φ'' = 38 º. Izračunaj delovno moč, ohmsko upornost in induktivnost porabnika.|||</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><latex><del class="diffchange diffchange-inline">DANE</del>\, = \,S \,\cdot \,\cos \varphi \, =\, 100\, \cdot \,\cos 38^{\,\circ} \, = \,{\rm{78,8\,W}}</latex></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><latex><ins class="diffchange diffchange-inline">P</ins>\, = \,S \,\cdot \,\cos \varphi \, =\, 100\, \cdot \,\cos 38^{\,\circ} \, = \,{\rm{78,8\,W}}</latex></div></td></tr>
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><latex>S \,= \,U \,\cdot\, I \,= \,\frac{U^2}{Z} \,\,\,\,\,\Rightarrow \,\,\,\,\,Z\, =\, \frac{U^2}{S}\, =\, \frac{{230}^2}{100} \,=\, 484\,\Omega </latex></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><latex>S \,= \,U \,\cdot\, I \,= \,\frac{U^2}{Z} \,\,\,\,\,\Rightarrow \,\,\,\,\,Z\, =\, \frac{U^2}{S}\, =\, \frac{{230}^2}{100} \,=\, 484\,\Omega </latex></div></td></tr>
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2010-10-27T07:07:50Z
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>1. Porabnik z zaporedno vezavo upora in tuljave obremenjuje električno omrežje 230 V/50 Hz z močjo 100 VA in povzroča fazni kot ''φ'' = 38 º. Izračunaj delovno moč, ohmsko upornost in induktivnost porabnika.|||</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>1. Porabnik z zaporedno vezavo upora in tuljave obremenjuje električno omrežje 230 V/50 Hz z močjo 100 VA in povzroča fazni kot ''φ'' = 38 º. Izračunaj delovno moč, ohmsko upornost in induktivnost porabnika.|||</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><latex><del class="diffchange diffchange-inline">P</del>\, = \,S \,\cdot \,\cos \varphi \, =\, 100\, \cdot \,\cos 38^{\,\circ} \, = \,{\rm{78,8\,W}}</latex></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><latex><ins class="diffchange diffchange-inline">DANE</ins>\, = \,S \,\cdot \,\cos \varphi \, =\, 100\, \cdot \,\cos 38^{\,\circ} \, = \,{\rm{78,8\,W}}</latex></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><latex>S \,= \,U \,\cdot\, I \,= \,\frac{U^2}{Z} \,\,\,\,\,\Rightarrow \,\,\,\,\,Z\, =\, \frac{U^2}{S}\, =\, \frac{{230}^2}{100} \,=\, 484\,\Omega </latex></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><latex>S \,= \,U \,\cdot\, I \,= \,\frac{U^2}{Z} \,\,\,\,\,\Rightarrow \,\,\,\,\,Z\, =\, \frac{U^2}{S}\, =\, \frac{{230}^2}{100} \,=\, 484\,\Omega </latex></div></td></tr>
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2010-09-04T18:14:26Z
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<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">'''Primeri:'''</del></div></td><td colspan="2"> </td></tr>
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2010-09-03T18:35:06Z
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<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>eele_animacija_024_RL_vezje_zaporedno_moci.swf|Moči v zaporedni vezavi upora in tuljave||eele_animacija_025_RC_vezje_zaporedno_moci.swf|Moči v zaporedni vezavi upora in kondenzatorja||eele_animacija_004_RLC_vezje_zaporedno_moci.swf|Moči v zaporednem izmeničnem RLC krogu||eele_animacija_026_RL_vezje_vzporedno_moci.swf|Moči v vzporedni vezavi upora in tuljave||eele_animacija_027_RC_vezje_vzporedno_moci.swf|Moči v vzporedni vezavi upora in kondenzatorja||eele_animacija_005_RLC_vezje_vzporedno_moci.swf|Moči v vzporednem izmeničnem RLC krogu</animacija></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>eele_animacija_024_RL_vezje_zaporedno_moci.swf|Moči v zaporedni vezavi upora in tuljave||</div></td></tr>
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>[[Image:eele_slika_3_3_3.svg|thumb|right|Slika 3.3.3: Trikotnik moči izmeničnega kroga s faznim kotom φ]]</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>[[Image:eele_slika_3_3_3.svg|thumb|right|Slika 3.3.3: Trikotnik moči izmeničnega kroga s faznim kotom φ]]</div></td></tr>
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2010-09-03T18:29:17Z
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>[[Image:eele_slika_3_3_3.svg|thumb|right|Slika 3.3.3: Trikotnik moči izmeničnega kroga s faznim kotom φ]]</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>[[Image:eele_slika_3_3_3.svg|thumb|right|Slika 3.3.3: Trikotnik moči izmeničnega kroga s faznim kotom φ]]</div></td></tr>
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><latex>S\, = \,\sqrt {{P^2} \,+ \,{Q_C}^2} \,\,\,\,\, \Rightarrow \,\,\,\,\,{Q_C}\, = \,\sqrt {{S^2} \,- \,{P^2}} \,= \,\sqrt {{{3,75}^2} \,- \,{3^2}} \,= \,{\rm{2,26\,mVAr}}</latex></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><latex>S\, = \,\sqrt {{P^2} \,+ \,{Q_C}^2} \,\,\,\,\, \Rightarrow \,\,\,\,\,{Q_C}\, = \,\sqrt {{S^2} \,- \,{P^2}} \,= \,\sqrt {{{3,75}^2} \,- \,{3^2}} \,= \,{\rm{2,26\,mVAr}}</latex></div></td></tr>
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2010-09-03T18:23:58Z
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2010-09-02T16:46:25Z
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2010-09-01T12:43:46Z
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